php - check if a file exists? check the name?

"William Tasso" <ngx.DeleteThis@tbdata.com> wrote in message
news:bgssct$rhv42$1@ID-139074.news.uni-berlin.de...
 > JakeC" <"SPAM-FlLTER wrote:
  > > ...
  > > Basically what I am doing is
  > > uploading a certain amount of pictures (amount varies day-to-day) to
  > > my website.
  > > ...
  > > I need the script to find out picture
  > > number part so it can find the maximum picture number (4 in the above
  > > example) and then show "next pic" until it gets to picture
  > > 2003-8-22a(maximum picture number).jpg or rather 2003-8-22a4.jpg
  > > which is the last picture for that day so "next pic" disappears.
 >
 > Load the file names into an array (any construct - any language) and count
 > them; then you wont care how they are named.
 >
 > --
<font color=purple> > William Tasso - <a style='text-decoration: underline;' href="http://WilliamTasso.com</font" target="_blank">http://WilliamTasso.com</font</a>>
 >

Yes I could do that but I want this to be completely handled by the system
since if I need to I could just look at the file names and find the largest
number which would be the amount of pictures and then manually enter that in
to the database using a form. The reason is that I will most likely
eventually have somebody else taking and uploading the photos and I do not
want to have to be looking through the files to find that particular days
photos and load them into an array or find the amount of photos. I could
also end up having over a hundred photos a day and that would take quite
some time to load all those files into an array or find the amount of
photos.<!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name? 

"JakeC" <"SPAM-FlLTER"jake-c@bigpond.net.au> wrote in message
news:QcmYa.18722$bo1.2784@news-server.bigpond.net.au...
 > Hey all,
 > I'm having a bit of a problem with my website so I was wondering if anyone
 > would be able to help.
 >
 > I'll give you a bit of background first. Basically what I am doing is
 > uploading a certain amount of pictures (amount varies day-to-day) to my
 > website. The pictures are named in the following format : (date)a(picture
 > number).jpg so for example, if it was the 22 August 2003 and I had
uploaded
 > 4 pictures that day, the pictures would be named:
 > 2003-8-22a1.jpg
 > 2003-8-22a2.jpg
 > 2003-8-22a3.jpg
 > 2003-8-22a4.jpg
 >
 > Now what I am having trouble with is that I want a script in which it
 > automatically finds the (picture number) part of the file name for the
 > pictures that were uploaded that particular day, which in the above
example
 > would be 1,2,3,4. This is because on the site, a "next pic" link comes up
if
 > there is another pictures available and disappears when on the last
picture.
 > I need the script to find out picture number part so it can find the
maximum
 > picture number (4 in the above example) and then show "next pic" until it
 > gets to picture 2003-8-22a(maximum picture number).jpg or rather
 > 2003-8-22a4.jpg which is the last picture for that day so "next pic"
 > disappears.
 >
 > This may seem hard to understand so please ask if you want me to write it
 > again.

You say you want a script to make the "next pic" link disappear, yet you
also say the site is presently doing this?? Is that part working or not?

There are 101 ways to achieve this, but if I was going to Dublin, I probably
wouldn't start from here.

You say you "want a script", are you looking for something ready made? I
imagine it would be very difficult to find something off-the-shelf that
would suit your exact requirements.

Are you writing the php yourself?

Since you are using a database, each pic will have its own record (row) you
can count the rows.
--
Charles Sweeney
<a style='text-decoration: underline;' href="http://www.CharlesSweeney.com" target="_blank">www.CharlesSweeney.com</a><!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name? 

In article <QcmYa.18722$bo1.2784@news-server.bigpond.net.au>, JakeC wrote:
 > Hey all,
 > I'm having a bit of a problem with my website so I was wondering if anyone
 > would be able to help.
 >
 > I'll give you a bit of background first. Basically what I am doing is
 > uploading a certain amount of pictures (amount varies day-to-day) to my
 > website. The pictures are named in the following format : (date)a(picture
 > number).jpg so for example, if it was the 22 August 2003 and I had uploaded
 > 4 pictures that day, the pictures would be named:
 > 2003-8-22a1.jpg
 > 2003-8-22a2.jpg
 > 2003-8-22a3.jpg
 > 2003-8-22a4.jpg
 >
 > Now what I am having trouble with is that I want a script in which it
 > automatically finds the (picture number) part of the file name for the
 > pictures that were uploaded that particular day, which in the above example
 > would be 1,2,3,4. This is because on the site, a "next pic" link comes up if
 > there is another pictures available and disappears when on the last picture.
 > I need the script to find out picture number part so it can find the maximum
 > picture number (4 in the above example) and then show "next pic" until it
 > gets to picture 2003-8-22a(maximum picture number).jpg or rather
 > 2003-8-22a4.jpg which is the last picture for that day so "next pic"
 > disappears.
 >
 > This may seem hard to understand so please ask if you want me to write it
 > again.
 >
 > Thanks for the help,
 > - Jake

Is this what you want.....

Use the directory function in php to read the files names into an array then
sort...

Then if you looking for pics from Aug 22nd 2003, check each element in the
array :

$j=0;

for ($i=0; $i < count($dir_array); $i++){

if (substr($dir_array[$i],0,9)==$dateformat)
$display_array[$j++]=$dir_array[$i];

}

$display_count=count($display_array);

then format and display the $display_array

kb<!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name? 

"Charles Sweeney" <me.RemoveThis@charlessweeney.com> wrote in message
news:bgt5q4$sece6$1@ID-162618.news.uni-berlin.de...

  > > This may seem hard to understand so please ask if you want me to write
it
  > > again.
 >
 > You say you want a script to make the "next pic" link disappear, yet you
 > also say the site is presently doing this?? Is that part working or not?
 >
 > There are 101 ways to achieve this, but if I was going to Dublin, I
probably
 > wouldn't start from here.
 >
 > You say you "want a script", are you looking for something ready made? I
 > imagine it would be very difficult to find something off-the-shelf that
 > would suit your exact requirements.
 >
 > Are you writing the php yourself?
 >
 > Since you are using a database, each pic will have its own record (row)
you
 > can count the rows.
 > --
 > Charles Sweeney
<font color=purple> > <a style='text-decoration: underline;' href="http://www.CharlesSweeney.com</font" target="_blank">www.CharlesSweeney.com</font</a>>





OK. I was in a rush when writing this so I expected it to be a bit hard to
understand. I'll try and explain it again.

A friend and I are currently developing a website in which he does the
graphic design and I do the programming (I have created websites using html,
javascript, css and ssi however this is my first attempt at using php and
mysql). The website is a daily surf report. It currently is 100% in php
however I have already setup a database in mysql and created a webpage so I
can add new data to it. I will add the database to it after I get the basics
of what I want to do down first.

What I want is the following. Once the pictures for the report are uploaded
to the server, Mysql or PHP then automatically finds how many pictures for
that day are on the server and saves this value to the database. That is
what I need help with. I have already made the script for making "next set"
disappear when it gets to the last set.

Hope you can understand
- Jake<!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name? 

"JakeC" <"SPAM-FlLTER"jake-c@bigpond.net.au> wrote in message
news:AOmYa.18771$bo1.107@news-server.bigpond.net.au...
 >
 > "William Tasso" <ngx.TakeThisOut@tbdata.com> wrote in message
 > news:bgssct$rhv42$1@ID-139074.news.uni-berlin.de...
  > > JakeC" <"SPAM-FlLTER wrote:
   > > > ...
   > > > Basically what I am doing is
   > > > uploading a certain amount of pictures (amount varies day-to-day) to
   > > > my website.
   > > > ...
   > > > I need the script to find out picture
   > > > number part so it can find the maximum picture number (4 in the above
   > > > example) and then show "next pic" until it gets to picture
   > > > 2003-8-22a(maximum picture number).jpg or rather 2003-8-22a4.jpg
   > > > which is the last picture for that day so "next pic" disappears.
  > >
  > > Load the file names into an array (any construct - any language) and
count
  > > them; then you wont care how they are named.
  > >
  > > --
<font color=green>  > > William Tasso - <a style='text-decoration: underline;' href="http://WilliamTasso.com</font" target="_blank">http://WilliamTasso.com</font</a>>
  > >
 >
 > Yes I could do that but I want this to be completely handled by the system
 > since if I need to I could just look at the file names and find the
largest
 > number which would be the amount of pictures and then manually enter that
in
 > to the database using a form. The reason is that I will most likely
 > eventually have somebody else taking and uploading the photos and I do not
 > want to have to be looking through the files to find that particular days
 > photos and load them into an array or find the amount of photos. I could
 > also end up having over a hundred photos a day and that would take quite
 > some time to load all those files into an array or find the amount of
 > photos.
 >
Are you using (able to ) a DB? which??

If you are using MySql with PhP I can give you an answer:-)<!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name? 

 >
 > Is this what you want.....
 >
 > Use the directory function in php to read the files names into an array
then
 > sort...

Sort of. I want php to read the files names FOR A PARTICULAR DAY into an
array then sort AND COUNT them.

 >
 > Then if you looking for pics from Aug 22nd 2003, check each element in the
 > array :
 >
 > $j=0;
 >
 > for ($i=0; $i < count($dir_array); $i++){
 >
 > if (substr($dir_array[$i],0,9)==$dateformat)
 > $display_array[$j++]=$dir_array[$i];
 >
 > }
 >
 > $display_count=count($display_array);
 >
 > then format and display the $display_array
 >

I tried this code and came up with the following errors:
PHP Notice: Undefined variable: dir_array in C:\httpd\HTDOCS\index.php on
line 29
PHP Notice: Undefined variable: display_array in C:\httpd\HTDOCS\index.php
on line 36

Thanks for the help though see above and everyone else who replied to this
post. It is greatly appreciated!<!-- ~MESSAGE_AFTER~ -->
 >> Stay informed about: php - check if a file exists? check the name?