Cron Jobs -> Config Question

External Since: Feb 04, 2004 Posts: 2

I hope someone in this group can help. I am familiar with running cron
jobs, but have run into a particular syntax that I cannot get around. I
need to run a file on my server a couple of times a day. The file is a PHP
file, but it requires several arguments after the file name ....
file.php?a=1&b=2&c=3. First I tried simply entering this string into the
crontab, but got nothing (like this: php
/home/mySite/.../file.php?a=1&b=2&c=3 [where '...' is me truncating the
address for this post]).

Then I put this command into an .sh file like this:

#!/bin/bash
php
/home/mySite/public_html/bin/export.php?db=all&db_list=&comments=none&tables
=on&data=on

After which, I entered this into my Cron Manager like this: sh
/home/mySite/.../file.sh <-name of my sh file. Still, this job will not
run.

Any ideas on how to run a cron job like the one I am working with here?

Much thanks!
Kevin Mc.

External Since: Feb 04, 2004 Posts: 2

i took the long way around, and edited the PHP file ... removing all "if /
elseif" statements and simply hard-coded the results i wanted. it worked
like a charm.

thanks to all for your help.
KMc